Question of the day

What will be the number of products (excluding stereoisomers) in the given reaction? C₆H₅CHO + CH₃-CHO + NaOH → Product

First product will be formed by cross aldol where nucleophile (–OH) will attack at different type or reactant molecule. Second type of product will be formed aldol condensation where reaction will occur between same type of molecule.

1 2 3 4 5